Questions
Radius of curvature of first surface of double convex lens is 4 times that of the other If the focal length of the lens is 20 cm and refractive index of the lens is
detailed solution
Correct option is A
R1=4R2⇒R2=R14 1f=(μ−1)(1R1+1R2) =12(1R1+4R1) 12010=52R1⇒R1=50cmTalk to our academic expert!
Similar Questions
A plano convex lens fits exactly into a plano concave lens. Their plane surfaces are parallel to each other. If lenses are made of different materials of refractive indices and and R is the radius of curvature of the curved surface of the lenses, then the focal length of the combination is
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