The radius of curvature of the left and right surface of the concave lens are 10 cm and 15 cm respectively. The radius of curvature of the mirror is 15 cm
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a
equivalent focal length of the combination is –18 cm
b
equivalent focal length of the combination is +36 cm
c
the system behaves like a concave mirror
d
the system behaves like a convex mirror
answer is A.
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Detailed Solution
−1F=P=2Pl1+2Pl2+Pm………….(1)P11=1f1=(μ−1)1R1−1R2PL1=(1.5−1]−110−115=−112…(2)PL2=1f2=(μ−1)1R1−1R2Pl2=43−1215=245…………(3)Pm=−1f=+215………………..(4)−1F=P=2−112+245+215=−16+445+215=118F = -18cm. Focus is negative means system will behave as concave mirror.
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The radius of curvature of the left and right surface of the concave lens are 10 cm and 15 cm respectively. The radius of curvature of the mirror is 15 cm