First slide

Motion of a charged particle

Question

The radius of curvature of the path followed by a charge particle in magnetic field is proportional to

Moderate

A

Charge of the particle
B

Momentum of the particle
C

Energy of the particle
D

Magnetic field density

Solution

$C e n t r i p e t a l f o r c e i s b a l a n c e d b y m a g n e t i c f o r c e \frac{M V^{2}}{r} = B q V \Rightarrow \frac{M V}{r} = B q \Rightarrow M V = P = B q r \Rightarrow r α P, r α \frac{1}{B}, r α \frac{1}{q}$

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