The radius of the first permitted Bohr orbit, for the electron, in a hydrogen atom equals 0.51 Å and its ground state energy equals–13.6 eV. If the electron in the hydrogen atom is replaced by muon (μ–) [charge same as electron and mass 207 me], the first Bohr radius and ground state energy will be,

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2.56×10−13m,−13.6eV

0.53×10−13m,−3.6eV

25.6×10−13m,−2.8eV

2.56×10−13m,−2.8keV

answer is D.

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Detailed Solution

rn∝1mrμ=0.51207≃2.56×10−13mE∝me(E)μ=−13.6×207 =−2.8keV

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