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Q.

The radius of gyration of a uniform rod of length  l, about an axis passing through a point  L4 away from the center of the rod, and perpendicular to it is

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a

748L

b

38L

c

18L

d

14L

answer is A.

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Detailed Solution

Using Parallel Axis Theorem,  IC+Md2 =IP ⇒ML212+ML42=MK2   here K = Radius of Gyration⇒L212+L216=K2           ⇒ K=748L
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The radius of gyration of a uniform rod of length  l, about an axis passing through a point  L4 away from the center of the rod, and perpendicular to it is