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The radius of hydrogen atom in its ground state is 5.3×10-11m. After collision with an electron it is found to have a radius of 21.2×10-11m. What is the principal quantum number n of the final state of the atom

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a

n = 4

b

n = 2

c

n = 16

d

n = 3

answer is B.

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Detailed Solution

r∝n2 i.e.rfri=nfni2 ⇒21.2×10-115.3×10-11=n12⇒n2=4⇒n = 2
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The radius of hydrogen atom in its ground state is 5.3×10-11m. After collision with an electron it is found to have a radius of 21.2×10-11m. What is the principal quantum number n of the final state of the atom