The radius of nucleus of silver (atomic number = 47) is 3.4×10−14m. The electric potential on the surface of nucleus is (e=1.6×10−19C)

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1.99×106 volt

2.9×106 volt

4.99×106 volt

0.99×106 volt

answer is A.

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Detailed Solution

V=14πε0⋅(Ze)r=9×109×47×1.6×10−193.4×10−14=1.99×106V

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