The radius of nucleus of silver (atomic$$ number $$=$$ $$47) is $$3.4$$×$$10$$−$$14m$$. The electric potential on the surface of nucleus is (e=1.6$$×$$10$$−$$19C)

Correct option is 11.99×106 volt

Questions

The radius of nucleus of silver (atomic number = 47) is $3 .4 \times 10^{- 14} m$ . The electric potential on the surface of nucleus is $(e = 1 .6 \times 10^{- 19} C)$

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detailed solution

Correct option is A

V=14πε0⋅(Ze)r=9×109×47×1.6×10−193.4×10−14=1.99×106V

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The radius of nucleus of silver (atomic number = 47) is 3.4×10−14m. The electric potential on the surface of nucleus is (e=1.6×10−19C)

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The radius of nucleus of silver (atomic number = 47) is $3 .4 \times 10^{- 14} m$ . The electric potential on the surface of nucleus is $(e = 1 .6 \times 10^{- 19} C)$