Q.
The radius of nucleus of silver (atomic number = 47) is 3.4 x 10-14m. The electric potential on the surface of nucleus is (e = 1.6 x 10-19C)
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a
1.99 x 106 volt
b
2.9 x 106 volt
c
4.99 x 106 volt
d
0.99 x 106 volt
answer is A.
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Detailed Solution
V=14πε0·(Ze)r=9×109×47×1.6×10-193.4×10-14=1.99×106 V
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