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The radius R of a nucleus of mass number A can be estimated by the formula $R = (1.3 \times 10^{- 15}) A^{1 / 3} m$ . It follows that the mass density of a nucleus is of the order of : $(M_{prot} ≅ M_{neut} = 1.67 \times 10^{- 27} kg)$

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detailed solution

Correct option is A

density =MPVP=1.67×10-27×A43π1.3×10-153(A)kg/m3=3×1.674π×(1.3)3×1018 kg/m3=30×1.674π(1.3)3×1017 kg/m3∴d=1.81×1017 kg/m3

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The radius R of a nucleus of mass number A can be estimated by the formula R = (1.3 × 10–15)A1/3 m. It follows that the mass density of a nucleus is of the order of : Mprot ≅Mneut =1.67×10-27 kg

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Ready to Test Your Skills?

free study material

The radius R of a nucleus of mass number A can be estimated by the formula $R = (1.3 \times 10^{- 15}) A^{1 / 3} m$ . It follows that the mass density of a nucleus is of the order of : $(M_{prot} ≅ M_{neut} = 1.67 \times 10^{- 27} kg)$