Questions
The radius of the second orbit of an electron in hydrogen atom is 2.116 . The de-Broglie wavelength associated with this electron in this orbit would be
detailed solution
Correct option is A
mvr=2h2ππr=hmV=hp=λ, 3.14×2.116=6.64AOTalk to our academic expert!
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An electron is orbiting in 4th energy state in a hydrogen atom. The de-Broglie wavelength associated with this electron is nearly equal to
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