The radius of the second orbit of an electron in hydrogen atom is 2.116 A0. The de-Broglie wavelength associated with this electron in this orbit would be

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6.64 A0

1.058A0

20116 A0

13.28 A0

answer is A.

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Detailed Solution

mvr=2h2ππr=hmV=hp=λ, 3.14×2.116=6.64AO

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