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Q.

The radius of a soap bubble is increased from 1π cm to 2πcm. If the surface tension of water is 30 dynes per cm, then the work done will be

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a

180 ergs

b

360 ergs

c

720 ergs

d

960 ergs

answer is C.

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Detailed Solution

W = 8πT(r22 - r12) = 8πT[(2π)2-(1π)2]∴ W = 8 ×π×30×3π = 720 ergs
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