First slide

Pontial due to

Question

The radius of a soap bubble whose potential is 16V is doubled. The new potential of the bubble will be

Moderate

A

2 V
B

4 V
C

8 V
D

16 V

Solution

$Potential V \propto \frac{1}{r} \Rightarrow V^{'} = \frac{V}{2} = 8 V$

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