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Questions  

The radius of a sphere is (5.3±0.1) cm. The percentage error in its volume is

a
0.15.3×100
b
3×0.15.3×100
c
0.1×1003.53
d
3+0.15.3×100

detailed solution

Correct option is B

∴V = 43πr3∴% error in volume= 3×% error in radius= 3×0.15.3×100

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