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Accuracy; precision of instruments and errors in measurements

Question

The radius of a sphere is measured to be  7.50±0.85cm. Suppose the percentage error in its volume is x. The value of x, to the nearest x, is_____

Easy
Solution

 Volume of sphere, V=43πR3ΔVV=3Δrr ΔVV×100=3Δrr×100ΔVV×100=3×0.857.50×100=34%



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