The radius of a sphere is measured to be 7.50±0.85cm. Suppose the percentage error in its volume is x. The value of x, to the nearest x, is_____

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answer is 34.

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Detailed Solution

Volume of sphere, V=43πR3ΔVV=3Δrr ⇒ΔVV×100=3Δrr×100⇒ΔVV×100=3×0.857.50×100=34%

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