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The radius of a sphere is measured as (10±4%) . The error in the measurement of its volume is

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a
5.02 cc
b
50. 2 cc
c
0.502cc
d
251. 2 cc

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detailed solution

Correct option is B

V=43πr3 ΔVV×100=3Δrr×100ΔV=43πr3×3×Δrr=43×227×(10)3×3×0.0410=4×227×4=50.2 cc


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