First slide
Potential energy
Question

The radius of a well is 7m. Water in it is at a depth of 20m and depth of water column is 10m. Work done in pumping out water completely from the well is, (g = 10ms–2)

Moderate
Solution

\large w = mg\frac{h}{2} = \left( {v\rho } \right)g\frac{h}{2} = \frac{{22}}{7} \times {7^2} \times 10 \times {10^3} \times 10 \times \left( {20 + \frac{{10}}{2}} \right)J
\large = 385 \times {10^6}J

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