A railway track runs parallel to a road until a turn brings the road to railway crossing. A cyclist rides along the road every day at a constant speed $$20$$ $$km/hr$$. He normally meets a train that travels in same direction at the crossing. One day he was late by $$25$$ minutes and met the train $$10$$ km before the railway crossing. Find the speed of the train.

Question

Infinity Learn · Accepted Answer

tcycle $$=$$ $$10km20$$ kmh−$$1$$ $$=$$ $$12h$$  $$=$$ $$30$$ minΔ$$t=$$ $$5$$ min $$=$$ $$560hrTrain$$ running as per schedule.So  Vtrain $$=$$ $$10(560)$$ $$=$$ $$10$$×$$605$$ $$=$$ $$120$$ kmh−$$1$$

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