The range of a particle when launched at an angle of 15∘with the horizontal is 1.5 km. What is the range of the projectile when launched at an angle of 45o to the horizontal
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a
1.5 km
b
3.0 km
c
6.0 km
d
0.75 km
answer is B.
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Detailed Solution
or R1=u2sin2θg=u2sin30g1⋅5=u22g or u2g=3R2=u2sin90g=u2g=3km