Questions
The range of a projectile fired at an angle of 15° is 50 m. If it is fired with the same speed at an angle of 45°,its range will be
detailed solution
Correct option is B
R1=u2sin2θ1g;R2=u2sin2θ2gR2R1=sin2θ2sin2θ1=sin2×45∘sin2×15∘=sin90∘sin30∘=11/2=2R2=2R1=2×50=100m.Talk to our academic expert!
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