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Questions  

The range of a projectile fired at an angle of  15° is 50 m. If it is fired with the same speed at an angle of 45°,its range will be

a
50 m
b
100 m
c
25 m
d
37 m

detailed solution

Correct option is B

R1=u2sin⁡2θ1g;R2=u2sin⁡2θ2gR2R1=sin⁡2θ2sin⁡2θ1=sin⁡2×45∘sin⁡2×15∘=sin⁡90∘sin⁡30∘=11/2=2R2=2R1=2×50=100m.

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