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Q.

The range of a projectile fired at an angle of  15° is 50 m. If it is fired with the same speed at an angle of 45°,its range will be

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a

50 m

b

100 m

c

25 m

d

37 m

answer is B.

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Detailed Solution

R1=u2sin⁡2θ1g;R2=u2sin⁡2θ2gR2R1=sin⁡2θ2sin⁡2θ1=sin⁡2×45∘sin⁡2×15∘=sin⁡90∘sin⁡30∘=11/2=2R2=2R1=2×50=100m.
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