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Question

The rate of disintegration was observed to be 1017 disintegrations per sec when its half life period is 1445 years. 
The original number of particles are

Difficult
Solution

Rate of disintegration dNdt=1017s-1

Half life T1/2=1445 year

=1445 x 365 x 24 x 60 x 60 =4.55 x 1010sec

Now decay constant

λ=0.693T1/2=0.934.55 x 1010=1.5 x 10-11 per sec

The rate of disintegration

dNdt=λ x N01017=1.5 x 10-11 x N0 N0=6.6 x 1027.

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