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Q.

The rate of flow of a liquid through a capillary tube of radius r is V when the pressure difference is P. If the  radius is reduced to r/2 and the pressure increases to 2 P1 then the rate of flow becomes

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a

V

b

V/2

c

V/4

d

V/8

answer is D.

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Detailed Solution

V=πPr48ηl Ia second case V1=π(2P)(r/2)48ηl=πPr48ηl×18=V8
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