First slide

Viscosity

Question

The rate of flow of a liquid through a capillary tube of radius r is V when the pressure difference is P. If the radius is reduced to r/2 and the pressure increases to 2 P₁ then the rate of flow becomes

Easy

A

V
B

V/2
C

V/4
D

V/8

Solution

$V = \frac{{πPr}^{4}}{8 ηl} Ia second case V_{1} = \frac{π (2 P) (r / 2)^{4}}{8 ηl} = \frac{{πPr}^{4}}{8 ηl} \times \frac{1}{8} = \frac{V}{8}$

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