The rate of flow of a liquid through a capillary tube of radius r is V when the pressure difference is P. If the radius is reduced to r/2 and the pressure increases to 2 P1 then the rate of flow becomes
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a
V
b
V/2
c
V/4
d
V/8
answer is D.
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Detailed Solution
V=πPr48ηl Ia second case V1=π(2P)(r/2)48ηl=πPr48ηl×18=V8