The rate of flow of water through the tube shown is 1000 cm3/s. The area of cross-section at point A and B are 10 cm2 and 4 cm2. The difference in mercury level (h) in the tube is ______cm. g=10m/s2, ρHg=13600kg/m3, ρH2O=103kg/m3

Applying equation of continuity A1v1=A2v2=QAs Q=1000cm3/s,A1=10cm2,A2=4cm2vA=100cm/s,vB=250cm/sApplying Bernoulli's theorem at A and B.PA+12ρvA2=PB+12ρvB2 (both points are at the same level)∴ PA−PB=12ρvB2−vA2PA−PB can also be approximately written as hρHgg∴ hρHgg=12ρH2OvB2−vA2⇒ h(13600)10=121000(2.50)2−(1.00)2⇒h≃1.93cm