The rate of steady volume flow of water through a capillary tube of length 'l' and radius 'r' under a pressure difference of P is V. This tube is connected with another tube of the same length but half the radius in series. Then the rate of steady volume flow through them is (The pressure difference across the combination is P)
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a
V16
b
V17
c
16V17
d
17V16
answer is B.
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Detailed Solution
Rate of flow of liquid V=PRwhere liquid resistance R=8ηlπr4For another tube liquid resistance R'=8ηlπr24=8ηlπr4.16=16RFor the series combination VNew=PR+R'=PR+16R=P17R=V17.