Q.
The rate of steady volume flow of water through a capillary tube of length ‘l’ and radius ‘r’ under a pressure difference of P is V. This tube is connected with another tube of the same length but half the radius in series. Then the rate of steady volume flow through them is (The pressure difference across the combination is P)
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a
V16
b
V17
c
16V17
d
17V16
answer is B.
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Detailed Solution
R1=8ηlπr4=R R2=8ηlπr24=16R when both are connected in series Volume rate =V2=ΔPR1+R2=PR+16R=P17R=V17