The rate of steady volume flow of water through a capillary tube of length ‘l’ and radius ‘r’ under a pressure difference of P is V. This tube is connected with another tube of the same length but half the radius in series. Then the rate of steady volume flow through them is (The$$ pressure difference across the combination is $$P)

Question

The rate of steady volume flow of water through a  capillary tube of length ‘l’ and radius ‘r’ under a pressure difference of P  is V. This tube is connected with another tube of the same length but half  the radius in series. Then the rate of steady volume flow through them is  (The$$ pressure difference across the combination is $$P)

Infinity Learn · Accepted Answer

$$R1=8$$ηl$$π$$$$r4=R$$ $$R2=8$$ηl$$π$$$$r24=16R$$  when both are connected in series  Volume rate $$=V2=$$Δ$$PR1+R2=PR+16R=P17R=V17$$

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