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The ratio activity of an element  becomes 1/64 th of its original value in 60 sec. Then the half-life period is

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a
5 sec
b
10 sec
c
20 sec
d
30 sec

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detailed solution

Correct option is B

A=A012tT1/2⇒164=1260T1/2 ⇒126=1260T1/2⇒T1/2=10 sec


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