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Questions  

The ratio of average translational KE to rotational KE of a linear polyatomic molecule at temperature T is

a
3 : 1
b
5 : 1
c
3 : 2
d
7 : 5

detailed solution

Correct option is C

For poly atomic linear molecule, number of degrees of freedom for translational motion is 3 and that for rotational motion is 2.∴The ratio = 3 x KT22 x KT2=32

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