The ratio of diameters of two wires of same material is n : 1. The length of wires are 4 m each. On applying the same load, the increase in length of thin wire will be
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a
n2 times
b
n times
c
2n times
d
None of the above
answer is A.
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Detailed Solution
l∝FLr2Y⇒l∝1r2 (F,L and Y are constant )l2l1=r1r22=(n)2⇒l2=n2l1