The ratio of the dimensions of Planck's constant and that of moment of inertia has the dimensions of  [KCET 2015]

We know that, energy of an emitted particle,               E = hv  ⇒h =EvPlanck's constant, [h]=ML2 T-2T-1=ML2 T-1                        …(i)and moment of inertia, I = mr2  ⇒ [I] = [ML2]                               …(ii)On dividing Eq. (i) by Eq. (ii), we get                   [h]I]=ML2 T-1ML2=T-1=1 Ti.e.              [h][I]=T-1=Dimensions of frequency of a particle