The ratio of distance covered by a body in 1S, 2S, 3S,.......ns is
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a
1:4:9:.....n2
b
1:2:3:......n
c
1:12:13:.......1n
d
1:1:1:....
answer is A.
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Detailed Solution
equation of motion, S=Ut+12gt2 initial velocity=U=0;acceleration due to gravity=g;time elapsed=t;displacement=S S=height=12gt2In 1st sec the distance traveled is, (put t=1 then) S1=12gt2=g2 In 2nd sec the distance traveled is,( put t=2 then) S2=12gt2=4g2 In 3rd sec the distance traveled is( put t=3 then) S3=12gt2=9g2S1:S2:S3:.......=g2:4g2:9g2:.......... S1:S2:S3:.......=1:4:9:161:4:9:........n2