Questions
The ratio of distance travelled by a freely fall body in 1st sec, 2nd sec, 3rd sec……..
detailed solution
Correct option is C
The distance travelled by freely falling body S=12gt2Distance in 1st sec is =g2 Distance in 2nd sec is 4g2−g2=3g2 Distance in 3rd sec is 9g2−4g2=5g2 The ratio of distance is g2:3g2:5g2=1:3:5:.....Talk to our academic expert!
Similar Questions
A particle is moving along the x-axis whose acceleration is given by , where x is the location of the particle. At t = 0, the particle is at rest at x = 4/3 m. The distance travelled by the particle in 5 s is
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