The ratio of distance travelled by a freely fall body in 1st sec, 2nd sec, 3rd sec……..
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a
1:2:3:.......
b
1:1:1:.........
c
1:3:5:...........
d
1:2:4:6.........
answer is C.
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Detailed Solution
The distance travelled by freely falling body S=12gt2Distance in 1st sec is =g2 Distance in 2nd sec is 4g2−g2=3g2 Distance in 3rd sec is 9g2−4g2=5g2 The ratio of distance is g2:3g2:5g2=1:3:5:.....