The ratio of distance travelled by a freely fallIing  body in 1st sec, 2nd sec, 3rd sec……..

The distance travelled by freely falling body, initial velocity=U=0; S=12gt2 ;  acceleration due to gravity=g;time elapsed=t;displacement=S Distance in 1st sec is =g2 Distance in 2nd sec is 4g2−g2=3g2  Distance in 3rd sec is  9g2−4g2=5g2 The ratio of distance is  g2:3g2:5g2=1:3:5:.....