The ratio of Earth’s orbital angular momentum (about the sun) to its mass is  4.4×1015 m2/s. The area enclosed by the earth’s orbit is  N×1023 m2. Find the value of N ?

GivenAngular momentum per mass LM=4.4×1015 m2/sBy Kepler’s second law we use Areal velocity =  Area SweptTime for one Revolution of Earth about the sun Also we use Areal velocity =  L2M⇒ Area Swept =  L2M (Time for one Revolution of Earth about the sun) ⇒ Area Swept =  124.4×1015365×24×60×60⇒ Area Swept =  0.69×1023 m2