First slide
NA
Question

The ratio of electric fields due to an electric dipole at equal distances in its axial and equatorial position will be

Easy
Solution

For a dipole E=14πε0r3×p1+3cos2θ
 Ea=2p4πε0r3 (θ=0)
and   Ee=p4πε0r3 (θ=90)
 EaEe=2:1

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