First slide

Electrostatic force

Question

The ratio of the forces between two small spheres with constant charge (a) in air (b) in a medium of dielectric constant K is

Easy

A

1 : K
B

K : 1
C

$1 : K^{2}$
D

$K^{2} : 1$

Solution

$F_{a} = \frac{q_{1} q_{2}}{4 {πε}_{0} r^{2}}, F_{b} = \frac{q_{1} q_{2}}{K 4 {πε}_{0} r^{2}} \Rightarrow F_{a} : F_{b} = K : 1$

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