The ratio of ionization energy of Bohr's hydrogen atom and Bohr's hydrogen-like lithium atom is
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a
1 : 1
b
1 : 3
c
1 : 9
d
None of these
answer is C.
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Detailed Solution
Energy of an electron in ground state of an atom (Bohr's hydrogen-like atom) is given as E=−13.6Z2 eVZ=atomic number of the atom⇒Eionisation=13.6Z2⇒EionHEionLi=ZHZLi2=132=19