The ratio of kinetic energy to the potential energy of a particle executing SHM at a distance equal to half its amplitude, the distance being measured from its equilibrium position is

Let the amplitude of SHM be A.Now, potential energy of SHM, U=12kx2Here,  x=A2⇒U=12kA24                                           …(i)Kinetic energy K=12kA2-12kA24⇒K=38kA2         …(ii)On dividing Eq. (ii) by Eq. (i), we get                     KU=38×81⇒KU=31