The ratio of lateral contractional strain and the longitudinal elongational strain of a stretched wire is
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a
1 /2
b
1
c
2
d
3 /2
answer is A.
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Detailed Solution
The volume of the wire before stretching and after stretching remains the same. HenceπR2L=π(R−ΔR)2(L+ΔL)where ∆L = elongation in wire, and∆R = contraction in radius after stretchingNow L+ΔLL=R2(R−ΔR)2 or 1+ΔLL=1+2ΔRROr ΔLL=2ΔRR∴ (ΔR/R)(ΔL/L)= Contractional strain Longitudinal strain =12