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Q.

The ratio of longest wavelength and the shortest wavelength observed in the five spectral series of emission spectrum of hydrogen is

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a

43

b

523376

c

25

d

90011

answer is D.

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Detailed Solution

Shortest wavelength comes from n1=∞ to n2=1 and longest wavelength comes from n1=6 to n2=5 in the given case. Hence 1λmin=R 112-1∞2=R 1λmax=R 152-162=R 36-2525×36=11900R∴λmaxλmin=90011
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