First slide

The bar magnet

Question

The ratio of magnetic fields due to a small bar magnet in the end-on position to broad-side-on position is

Moderate

A

1/4
B

1/2
C

1
D

2

Solution

$\begin{array}{l} B_{end on} = \frac{μ_{0}}{4 π} \times \frac{2 M}{d^{3}} \\ and B_{broad on} = \frac{μ_{0}}{4 π} \times \frac{M}{d^{3}} \end{array} ∴ \frac{B_{end on}}{B_{broad on}} = \frac{2}{1}$

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