Q.

The ratio of magnetic fields due to a small bar magnet in the end-on position to broad-side-on position is

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a

1/4

b

1/2

c

1

d

2

answer is D.

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Detailed Solution

Bend on =μ04π×2Md3 and Bbroad on =μ04π×Md3 ∴Bend on Bbroad on =21
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Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
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