First slide
Magnetic field due to a current carrying circular ring
Question

The ratio of magnetic induction on the axis of a circular current carrying coil of radius r to the magnetic induction at its centre will be

Easy
Solution

We know that 
Bx=μ0Nir22r2+x23/2 and B0=μ0Ni2r BXB0=r3r2+x23/2=11+x2/r23/2

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