The ratio of magnetic induction on the axis of a circular current carrying coil of radius r to the magnetic induction at its centre will be
11+x2r23/2
11+x2r21/2
11−X2r2−3/2
11+X2r2−1/2
We know that Bx=μ0Nir22r2+x23/2 and B0=μ0Ni2r∴ BXB0=r3r2+x23/2=11+x2/r23/2