Questions
The ratio of magnitudes of Electric field strength at
detailed solution
Correct option is C
Eax=k2pr3 Eeq=kpr3 here for point (2,0,0) ⇒r=2 EA=E1+E2=2k(1)23i^+k(3)23j^ EA=(k4)2+(3k8)2=7k8 EB=k16So EAEB=27Talk to our academic expert!
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