First slide

Bohr's atom model

Question

The ratio of maximum to minimum possible radiation energy in Bohr's hypothetical hydrogen atom is equal to

Moderate

A

2
B

4
C

4/3
D

3/2

Solution

$E_{max} = 13.6 eV; E_{min} = 13.6 (1 - \frac{1}{2^{2}}) = \frac{3}{4} \times 13.6 eV \Rightarrow \frac{E_{max}}{E_{min}} = \frac{4}{3}$

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