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Q.

Ratio of minimum kinetic energies of two projectiles of same mass is 4 : 1. The ratio of the maximum height attained by them is also 4 : 1. The ratio of their ranges would be :

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a

16 : 1

b

4 : 1

c

8 : 1

d

2 : 1

answer is B.

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Detailed Solution

KEmin1 KEmin2 =12mu12cos2⁡θ112mu22cos2⁡θ2=41⇒u1cos⁡θ1u2cos⁡θ2=21 PEmax1 PEmax2 =u12sin2⁡θ12gu22sin2⁡θ22g=41⇒u1sin⁡θ1u2sin⁡θ2=2 R1R2=u122sin⁡θ1cos⁡θ1gu222sin⁡θ2cos⁡θ2g=2×2
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