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The ratio of radii of nuclei ${}_{13}{AI}^{27} and {}_{52}X^{A} is 3 : 5$ .The number of neutrons in the nuclei of X will be

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Correct option is B

r∝A1/3⇒r1r2=A1A21/3⇒35=27A1/3⇒27125=27A⇒A=125Number of nuclei in atom X = A-52 = 125 - 52 = 73.

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The ratio of radii of nuclei AI27 13 and X A 52 is 3 : 5.The number of neutrons in the nuclei of X will be

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The ratio of radii of nuclei ${}_{13}{AI}^{27} and {}_{52}X^{A} is 3 : 5$ .The number of neutrons in the nuclei of X will be