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Q.

Ratio of shortest wavelength of Balmer series in a hydrogen atom to that of Lymann series in a He+ ion is

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a

1 : 4

b

8 : 1

c

1 : 8

d

16 : 1

answer is D.

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Detailed Solution

for any series shortest wavelength can be given by  1λ=RZ21n2-1∞  where R is the Rydberg's constant and Z is the atomic no.For Balmer series in hydrogen atom 1λ1=R122−1∝=R4For Lymann series of He+ is 1λ2=4R112-1∞∴ λ1λ2=4/R1/4R=16
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Ratio of shortest wavelength of Balmer series in a hydrogen atom to that of Lymann series in a He+ ion is