Ratio of shortest wavelength of Balmer series in a hydrogen atom to that of Lymann series in a He+ ion is
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a
1 : 4
b
8 : 1
c
1 : 8
d
16 : 1
answer is D.
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Detailed Solution
for any series shortest wavelength can be given by 1λ=RZ21n2-1∞ where R is the Rydberg's constant and Z is the atomic no.For Balmer series in hydrogen atom 1λ1=R122−1∝=R4For Lymann series of He+ is 1λ2=4R112-1∞∴ λ1λ2=4/R1/4R=16