Q.
Ratio of shortest wavelength of Balmer series in a hydrogen atom to that of Lymann series in a He+ ion is
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
a
1 : 4
b
8 : 1
c
1 : 8
d
16 : 1
answer is D.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
for any series shortest wavelength can be given by 1λ=RZ21n2-1∞ where R is the Rydberg's constant and Z is the atomic no.For Balmer series in hydrogen atom 1λ1=R122−1∝=R4For Lymann series of He+ is 1λ2=4R112-1∞∴ λ1λ2=4/R1/4R=16
Watch 3-min video & get full concept clarity