Questions
Ratio of shortest wavelength of Balmer series in a hydrogen atom to that of Lymann series in a ion is
detailed solution
Correct option is D
for any series shortest wavelength can be given by 1λ=RZ21n2-1∞ where R is the Rydberg's constant and Z is the atomic no.For Balmer series in hydrogen atom 1λ1=R122−1∝=R4For Lymann series of He+ is 1λ2=4R112-1∞∴ λ1λ2=4/R1/4R=16Talk to our academic expert!
Similar Questions
In a sample of ions, a Li++ ion electron in first Bohr orbit is excited to a level by a radiation of wavelength λ. When the ion gets de-excited to the ground state in all possible ways (including intermediate emissions), a total of six spectral lines are observed. What is the value of λ ?
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