Q.
The ratio of specific heats of a gas is γ . The change in internal energy of one mole of gas when the volume changes from v to 2v at constant pressure “p” is
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a
pvγ−1
b
pv
c
γ−1
d
pvγ
answer is A.
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Detailed Solution
ΔU=nCvΔT=nRΔTγ-1=PΔVγ-1=PV2-V1γ-1=P2V-Vγ-1=PVγ-1
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