Q.

The ratio of specific heats of a gas is γ . The change in internal energy of one mole of gas when the volume changes  from v to 2v at constant pressure “p” is

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a

pvγ−1

b

pv

c

γ−1

d

pvγ

answer is A.

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Detailed Solution

ΔU=nCvΔT=nRΔTγ-1=PΔVγ-1=PV2-V1γ-1=P2V-Vγ-1=PVγ-1
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