The ratio of tensions in the string connected to the block of mass m2 in Figure (a) and Figure (b) respectively, is (friction is absent everywhere): m1=50kg,m2=80kg and F=1000N]

In Figure (a): Let tension in the string is T1F−T1=m1a⇒1000−T1=50a     ......(i)T1−m2g=m2a⇒T1−80g=80a      .......(ii) From (i) and (ii) T1=1200013NIn Figure (b): Let tension in the string is T2. F+m1g−T2=m1a⇒ 1000+50g−T2=50a     .......(iii)T2−80g=80aT2−80g=80a           .......(iv)From (iii) and (iv),T2=1600013N⇒T1T2=1200016000=34