The ratio of time periods of oscillation of two magnets of same moment of inertia suspended in a magnetic field is 1 : 2. The ratio of their magnetic moments is
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a
4 : 1
b
1 : 4
c
2:1
d
1 : 2
answer is A.
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Detailed Solution
T=2π(I/MB)T′=2πI/M′B∴TT′2=M′M or 122=M′M or MM′=41