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Questions  

The ratio of wave length of a photon of energy E and DeBroglie wavelength of an electron of mass ‘m’ having the kinetic energy also E is : (Speed of light = c)

a
2mc2E
b
mc2E
c
2mc2E
d
mc2E

detailed solution

Correct option is A

for photon E=hν=hcλ   so      λphoton =hcEfor electron E= p22m  ; p=2mE  λelectron =hp=h2mEso  λphoton λelectron=hcEh2mE=2mc2E

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