Questions
The ratio of wave length of a photon of energy E and DeBroglie wavelength of an electron of mass ‘m’ having the kinetic energy also E is : (Speed of light = c)
detailed solution
Correct option is A
for photon E=hν=hcλ so λphoton =hcEfor electron E= p22m ; p=2mE λelectron =hp=h2mEso λphoton λelectron=hcEh2mE=2mc2ETalk to our academic expert!
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