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The ratio of wave length of second line of Balmer series to the third line of Lymann series in Hydrogen atom is

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a
98
b
9
c
5
d
3

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detailed solution

Correct option is C

For second line of Balmer series 1λ2=R122-142=3R16For third line of Lymann series 1λ3=R1-142=15R16∴λ2λ3=15R16x163R=5


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